🌗 Find The Work Done When A 25 Kg Weight

Time (t) = 25 s. Increase in potential energy = m g h. Find the work done by him. Take g = 9.8 m / s 2. View Solution. Q2. Calculate the weight of a boy of mass 50 kg on Earth's surface. (Use g = 10 m/s 2) View Solution. Q3. a boy weighing 40kg carries a box weighing 20kg to the top of a building 15m high in 25sec. calculate the power. The work done by gravity is the force due to gravity multiplied by the displacement. Now, gravity is directed downwards and that's the negative direction. So we write negative m g in place of gravity and multiply it by the displacement which is positive and upwards. So we have negative 1500 kilograms times 9.8 times 40 meters giving us negative A body is thrown vertically upwards. Its velocity goes on decreasing. Write the change in kinetic energy when its velocity becomes zero. 10. A force of 10 N moves a body with a constant speed of 2 m/s. Calculate the power of the. body. 11. What will be the kinetic energy of a body when its mass is made four times and the velocity is. 3 feet and height h = 8 feet. Assummg the tank is full, find the work it takes to pump the water out of the tank. Note: weight density of water is pg = 62.51bs/ft3 10. A spherical tank of radius 4 m is half full of a liquid that has density of 900 kg per cubic meter. Find the work done in pumping the water through a spout W = Work done ; F = Force = mg ; S = Displacement = 2 m; θ = Angle = 0° ↠ W = 25 × 9.8 × 2 × cos0° ↠ W = 490 × 1. ↠ W = 490. Hence, When a body carried to the same place by pushing it up an inclined plane making an angle of 0° with the ground then work done will be 490 J. If the value of g be 10 m s−2, the work done by her after climbing 2 m will be: Calculate the work done in lifting 200kg of water through a vertical height 6meters. A weightlifter is lifting weights of mass 200 kg up to a height of 2 metres. If g = 9.8 m s −2, calculate : (a) potential energy acquired by the weights. Force times distance by definition, is work. And 1/2 mv squared, I said this is called kinetic energy. And so, by definition, kinetic energy is the amount of work-- and I mean this is the definition right here. It's the amount of work you need to put into an object or apply to an object to get it from rest to its current velocity. Question. Calculate the work done by an 85.0-kg man who pushes a crate 4.00 m up along a ramp that makes an angle of 20^\circ 20∘ with the horizontal. (See Figure 7.34.) He exerts a force of 500 N on the crate parallel to the ramp and moves at a constant speed. Be certain to include the work he does on the crate and on his body to get up the Work done to lift a mass or weight using a rope or cable — Krista King Math | Online math help. To calculate the work done when we lift a weight or mass vertically some distance, we'll use the integration formula for work, where W is the work done, F (x) is the force equation, and [a,b] is the starting and ending height of the weight or mass. zChHLUV.

find the work done when a 25 kg weight